Order 45 = 3² · 5

0 / 2 paper-excluded 0 / 2 Lean-excluded odd candidate

Why a candidate

Order 45 = 3² · 5 is a candidate because it divides the following Theorem 6 maxima: 135.

From the paper (Macaj–Siran 2010)

Combines a 3²-Sylow (Lemma 17: Fix ∈ {singleton, Petersen}, |X| ∣ 81 or 27) and a 5-Sylow (Lemma 18 / Lem 3(1/4/6): Fix(ℤ₅) ∈ {empty, pentagon, HS}). Proposition 6 (p = 3, q = 5) constrains the 3 · 5 structure. Neither of the two order-45 groups is individually excluded — both paper-allowed.

Group classification

SmallGroupGroupDescriptionPaperLean
(45, 1)ℤ₄₅Cyclic; 3-Sylow ℤ₉.allowedopen
(45, 2)(ℤ₃)² × ℤ₅Abelian, rank 2; 3-Sylow ℤ₃².allowedopen

Project status

open — no natural-language proof or Lean formalization yet. See Contribute for pointers if you want to attack this case.